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Updated: 03:01 AM CT Jan 10, 2007 Posted: 10:44 PM CT Jan 09, 2007 Parsing URLs with Regular Expressions and the Regex Object And the Anatomy of a URI (Uniform Resource Identifier) Author: Steve Lautenschlager Snippet Regular Expressions Text and Strings C# .NET Browsers Web     Prev     1    2     Next    Example: Regular Expressions for Parsing URIs and URLs OK, we're finally here. The following method may be copied into the code behind file of your aspx page. Ensure there is a Label named lblOutput on your aspx page and call the TestParseURL method. Example: Parse a URL with C# Regex public void TestParseURL() { string url = "http://www.cambiaresearch.com" + "/Cambia3/snippets/csharp/regex/uri_regex.aspx?id=17#authority"; string regexPattern = @"^(?<s1>(?<s0>[^:/\?#]+):)?(?<a1>" + @"//(?<a0>[^/\?#]*))?(?<p0>[^\?#]*)" + @"(?<q1>\?(?<q0>[^#]*))?" + @"(?<f1>#(?<f0>.*))?"; Regex re = new Regex(regexPattern, RegexOptions.ExplicitCapture); Match m = re.Match(url); lblOutput.Text = "<b>URL: " + url + "</b><p>"; lblOutput.Text += m.Groups["s0"].Value + " (Scheme without colon)<br>"; lblOutput.Text += m.Groups["s1"].Value + " (Scheme with colon)<br>"; lblOutput.Text += m.Groups["a0"].Value + " (Authority without //)<br>"; lblOutput.Text += m.Groups["a1"].Value + " (Authority with //)<br>"; lblOutput.Text += m.Groups["p0"].Value + " (Path)<br>"; lblOutput.Text += m.Groups["q0"].Value + " (Query without ?)<br>"; lblOutput.Text += m.Groups["q1"].Value + " (Query with ?)<br>"; lblOutput.Text += m.Groups["f0"].Value + " (Fragment without #)<br>"; lblOutput.Text += m.Groups["f1"].Value + " (Fragment with #)<br>"; } The following is the output you should see on your aspx page when you run the above method. Example: Output URL: http://www.cambiaresearch.com/Cambia3/snippets/csharp/ regex/uri_regex.aspx?id=17#authority http (Scheme without colon) http: (Scheme with colon) www.cambiaresearch.com (Authority without //) //www.cambiaresearch.com (Authority with //) /Cambia3/snippets/csharp/regex/uri_regex.aspx (Path) id=17 (Query without ?) ?id=17 (Query with ?) authority (Fragment without #) #authority (Fragment with #)     Prev     1    2     Next